John Michell lecture

close
more_vert
Andy Norfolk A
Andy Norfolk May 7, 2016 11:12:13
Replying to tiompan

If you correct John Michell's grid bearing of 66.5 degrees to a true north bearing it comes out as 69.23 degrees which is very close indeed to the 69.36 degrees that I calculated.

And in case you, or anyone else is interested in order to calculate azimuth from declination the following formula was used: cos(azimuth) = (sin(declination) (sin(latitude) x sin(altitude)))/ (cos(latitude) x cos(altitude)).

T tiompan
tiompan May 7, 2016 11:33:56
Replying to Andy Norfolk

If you want to represent the cross quarter day sunrise on a map you would draw a line showing that azimuth at 68 degrees not the 66.5 which he did draw .The “ley line” is not on the same bearing as the sunrise but it is made to appear as being “significant “in the text , when it isn’t . He tried to suggest the two were the same , they weren't .

Yes I know the various formulae thanks , and that is why I pointed out that the actual bearing for the cross quarter day sunrise seen from Men an Tol is 68 degrees.